To a person walking at 2 kmph rain appears to fall vertically. When he doubles his speed ran appears to fall at 300 to vertical. The actual velocity of rain is
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Let i^ and j^ be unit vector in horizontal and vertical respectively.
Let velocity of rain vr=ai^+bj^
speed of rain=a2+b2−−−−−−√
Case I:
when relative velocity of rain w.r.t man is vertical
vrm=v¯r−v¯m
vm=3i^
vrm=(a−3)i^+bj^
Since vrm is vertical
a−3=0=>a=3
Case II:
when relative velocity is at 45∘
v¯m=6i^
vrm=(a−6)i^+bj^
=−3i^+bj^
Since tanθ=b−3
tan 45=1
=> |b|=3
Therefore Speed=32+32−−−−−−√=32–√
Hence d is the correct answer.
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