Question

To a salt Y a small quantity of NH4OH soln.is added slowly then in excess. A pale blue precipitate is formed which dissolves in excess to form clear inky blue solution. Identify the positive ion in the salt Y. ​

Answer 1

Answer:

CuSO4+2NH4OH→(NH4)2SO4+Cu(OH)2(pale−blue)

The cation present in solution B is Copper (Cu+2).

The color of solution B is Blue.

The pale blue precipitate of copper hydroxide dissolves in excess of ammonium hydroxide forming tetraamine copper [II] sulphate, an azure blue(deep blue) soluble complex salt.

Cu(OH)2+(NH4)2SO4+2NH4OH→[Cu(NH3)4]SO4+4H2O

Those metals which react with both alkalies as well as acids are called amphoteric metals e.g., Zn, Sn, Al etc. They react with caustic alkalies like NaOH, KOH on heating and liberates H2 gas. e.g.,

Answer 2

Answer:What he/her said is correct.

Explanation:☺