Question

to a system 10 calorie heat is supplied which perform expansion work done equivalent 40 Joule .calculate internal energy change.​

Answer 1

Answer:

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Explanation:

Solution:- (D) 120J

As the work is done by the system and heat is supplied to the system.

Therefore,

q=100 cal=420J

w=−300J

Now from first law of thermodynamics,

ΔU=q+W

∴ΔU=420+(−300)

⇒ΔU=120J

Hence the change in internal energy during the process is 120J.

Answer 2

Answer:

Heat supplied = q = -10cal

work =w = 40j

internal energy change = ∆U = ❓

∆U = q + w

= -10+40

= 30

• so internal energy change = ∆U = 30 J