Question

to a system 10 calorie heat is supplied which perform expansion work done equivalent 40 j. calculate the internal energy change​

Answer 1

Answer:

given =  heat supplied (q)= - 10 cal

             work (w) = 40j

to find= internal energy change,  ΔU

Solution,

apply the first law of thermodynamics ,

that is ,

ΔU = q + w

ΔU = 40 - 10j

ΔU = 30J

the internal energy change is 30joule.

Answer 2

Answer:

1. The sum of heat & work done (q + w) is a a) Path function b) State function c) Both d) None