Question

To accept a no. From the user and find and print whether that no. Is an Armstrong no. Or not?​

Answer 1

Answer:

Sorry I didn't understand the question

Answer 2

Armstrong number

Output:

Enter any number: 153

Armstrong number

Explanation:

Program:

val= int(input("Enter any number: "))  #defining variable val and input value by user

sum = 0  #defining variable sum and assign value 0

t=val #defining variable t and assign user input value  

while t > 0:  #defining loop to check Armstrong number  

  digit = t % 10   #give remainder

  sum += digit ** 3  #add value

  t //= 10   #give quotient

if val == sum:  #check value

  print("Armstrong number")  

else:  

  print("no an Armstrong number")  

Description:

• In the above code, a "val" variable is declared, which accepts an integer value from the user end.
• In the next line, two other variable "sum" and "t"  is declare, in which "t" holds, user input value, and use in while loop to check value.
• Inside the loop, it calculates the Armstrong number and uses if condition to checks, and prints its value.  

Learn more:

• What is Armstrong number: https://brainly.in/question/11304746