Question

to balance Al(OH)3 + HNO3 _____ Al(NO3)3 + H2O nomber of molecules HNO3 required vwill be

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The required number of $HNO_3$  molecules in the balanced reaction are 3.

Explanation:

A balanced chemical equation is the one that have the number of atoms in the reactants and products of the equation must be equal.

Given an acid - base reaction:

$Al(OH)_3 + HNO_3 \longrightarrow Al(NO_3)_3 + H_2O$

• First count the Aluminum(Al) atoms on both sides, both sides it is equal to 1.
• Count the oxygen atoms in reactants side, there are $3+3=6$

        In products side, there are $3\times3+1=10$

• Count the hydrogen atoms in reactants side, there are $3+1=4$

        In products side, there are 2 atoms.

• Next count the Nitrogen(N) atoms on both sides, on products side it is equal to 1 and in reactants it is 3.

So, let us multiply $HNO_3$ with 3, then on both sides, nitrogen atoms are same equal to 3.

$Al(OH)_3 + 3HNO_3 \longrightarrow Al(NO_3)_3 + H_2O$

Now oxygen in left side is $3+9=12$ and hydrogen is $3+3=6$, whereas in products side they are 10 and 2 respectively.

To balance hydrogen, we need to multiply, $H_2O$ with 3, that gives

$Al(OH)_3 + 3HNO_3 \longrightarrow Al(NO_3)_3 + 3H_2O$

So, hydrogens are 6 on each side.

And the oxygen is also 12 on both sides.

So, $Al(OH)_3 + 3HNO_3 \longrightarrow Al(NO_3)_3 + 3H_2O$ is the balanced equation.

Therefore, the required number of $HNO_3$  molecules are 3.

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