Physics, asked by arohi5125, 1 year ago

To bodies with kinetic energies in the ratio of 4:1 are moving with equal linear momentum the ratio of their masses is

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Answered by TheDreamCatcher

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K.E. = $\frac{p2}{2m}$

= $\frac{K.E.1}{K.E.2}$

= $\frac{m2}{m1}$

= $\frac{4}{1}$

= $\frac{m1}{m2}$

= $\frac{1}{4}$

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Answered by rutujabhosle69

K.E = p^2/2m

K.E1 = \frac{ {p1}^{2} }{2m}K.E1=2mp1 /2

K.E2 = \frac{ {p2}^{2} }{2m}K.E2= 2mp2 2

Given,

linear momentum is same

p1 = p2 = p( say)

Now,

\frac{K.E1}{K.E2} = \frac{ \frac{ {p}^{2} }{2m1} }{ \frac{ {p}^{2} }{2m2} }

K.E2

K.E1= 2m2p/ 22m1p 2

\frac{4}{1} = \frac{m2}{m1}

1:4

= m1m2

\frac{m1}{m2} = \frac{1}{4}

m2m1

= 4/= 1: 4

Answer is 1:4

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