Question

to break a wire, a force of 10^6 N/m^2 is required. If the density of the material is 3×10^3 kg/m^3 then the length of the wire which will break by its own weight will be

Answer 1

To break a wire , a force 10^6 N/m² is required.

means, stress required to break = 10^6 N/m²

we know, stress = force/area

force = weight of body = mg

mass = volume × density

and volume of wire = area × length

Let A is area and L is length of wire

then, volume of wire = AL

and then, mass of wire = $\rho AL$, where $\rho$ is density of wire.

now, force = weight of body = $\rho ALg$

so, stress = $\frac{\rho ALg}{A}$

or, stress = $\rho Lg$

or, 10^6N/m² = 3 × 10^3 kg/m³ × L × 10m/s²

or, L = 33.3 m

hence, length of wire which will break by its own weight will be 33.3 m

Answer 2

Answer:

L=33.3m

Explanation: