Question

To buy furniture for a new apartment, Sylvia Chang
borrowed 5000 at 11% per annum simple interest for 11
months. How much interest will she pay?
(a) 500
(b) 504.17
(c) 6050
(d) 605​

Answer 1

AnswEr:-

B) 504.17

She will pay Rs.504.17 as interest.

$\rule{200}{1}$

Given:-

• Principal (P) = Rs.5000
• Rate of interest (r) = 11% p.a.
• Time(n) = 11 months.

To find:-

• Simple interest = ?

Solution:-

Here,

⇒ Time (n) = 11 months.

⇒ Time (n) = 11/12 years.

Now we know,

$\star\:{\boxed{\rm{\blue{Simple \: interest = \dfrac{P \times r \times n}{100} }}}}$

• Plugging values:-

⇒ $\sf Simple\: interest = \dfrac{5000 \times 11 \times \dfrac{11}{12}}{100}$

⇒ $\sf Simple\: interest = 50 \times 11 \times \dfrac{11}{12}$

⇒ $\sf Simple\: interest = 550 \times \dfrac{11}{12}$

⇒ ${\underline{\boxed{\rm{\red{Simple \: interest = Rs.504.17 }}}}}$

$\therefore\underline{\textsf{She will pay {\textbf{Rs.504.17}} as interest }}$

$\rule{150}{2}$

More information:-

⇒ A = P(1 + r)ⁿ

⇒ CI = P(1 + r)ⁿ - P

⇒ CI = P - A

Answer 2

AnswEr :

504.17

$\bf{\red{\underline{\underline{\bf{Given\::}}}}}$

To buy furniture for a new apartment Sylvia chang borrowed Rs.5000 at 11% p.a. simple Interest for 11 months.

$\bf{\red{\underline{\underline{\bf{To\:find\::}}}}}$

The Interest will she pay.

$\bf{\red{\underline{\underline{\bf{Explanation\::}}}}}$

Formula use :

$\bf{\boxed{\sf{Simple\:Interest\:(S.I.)=\frac{P*R*T}{100} }}}}$

$\bf{We\:have}\begin{cases}\sf{Principal\:(P)=Rs.5000}\\ \sf{Time\:(T)=11\:month=\frac{11}{12} \:years}\\ \sf{Rate\:(R)=11\%}\end{cases}}$

A/q

$\mapsto\sf{S.I.=\dfrac{50\cancel{00}\times 11\times \frac{11}{12} }{\cancel{100}} }\\\\\\\mapsto\sf{S.I.=50\times 11\times \dfrac{11}{12} }\\\\\\\mapsto\sf{S.I.=50\times \dfrac{121}{12} }\\\\\\\mapsto\sf{S.I.=\cancel{\dfrac{6050}{12} }}\\\\\\\mapsto\sf{\red{S.I.=Rs.504.17}}$

Thus;

The Interest will she payed is Rs.504.17.