Physics, asked by Snehagupta4, 1 year ago

To carry how much charge between two points having potential difference equal to 220 V, 1760J of work done with explaination

Answers

Answered by magarasri6
15

Answer:

hello buddy here you go with your answer....

we get : V = W/Q

potential difference= work done/charge

so, charge, = workdone / potential difference

= 1760/220 = 8C

hope it helps... mark as brainilist buddy

THANK YOU......

Answered by nafibarli789
0

Answer:

The answer is 8C.

Explanation:

A potential difference exists in the difference in the amount of power that charge transports have between two points in a circuit. Estimated in Volts: Potential difference (p.d.) exists calculated in volts (V) and is even called voltage.

voltage: The amount of work accomplished by the electric field per unit charge in moving a charge between two points in the electric field $\Delta V=\frac{W}{q}$ also understood as a difference in potential energy.

W=q \Delta V, \\

q=\frac{W}{\Delta V}=\frac{1760 J}{220 V}=8 C .

Therefore, The answer is 8C.

#SPJ2

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