Physics, asked by anilkumarkonduparamb, 6 months ago

To cars travelling on a straight road cross a km stone A at the same time with the velocities 20m/s and 10m/s with constant acceleration of 1m/s and 2m/s respectively. If they cross another km stone B at the same instant, the distance between A and B is?

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Answered by swapnilnagargoje7499
0

Answer:Answer:600mExplanation:S1=s2uA=20m/suB=10m/saA=1m/s2aB=2m/s2uAt+1/2aAt^2=uBt+1/2aBt^220t+1/2*1*t^2= ... 10ms with constant accelerations of Ims and 2ms respectively. If they cross another kilometer stone B at the same instant, the distance between A and B is: ... S = 10t + t² = 200 + 400 = 600.

2 answers

Explanation:vAnswer:600mExplanation:S1=s2uA=20m/suB=10m/saA=1m/s2aB=2m/s2uAt+1/2aAt^2=uBt+1/2aBt^220t+1/2*1*t^2= ... 10ms with constant accelerations of Ims and 2ms respectively. If they cross another kilometer stone B at the same instant, the distance between A and B is: ... S = 10t + t² = 200 + 400 = 600.

2 answers

Answered by ankithdkr2005
0

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