Physics, asked by metairahul77, 4 months ago

to charge 1farard of capacitor with four columbus charges requires a potential difference of​

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Answered by mental42
0

Answer:

the potential difference between the plates of both capacitors is VA - VB = Vbat. We have C1 = Q1/Vbat and C2 = Q2/Vbat, where Q1 is the charge on capacitor C1, and Q2 is the charge on capacitor C2.

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