Question

To charge an object with a positive charge of 5*10-19C the no of electrons withdrawn from it will be

Answer 1

Answer:

The no of electrons are three.

Explanation:

Given , q=5*10-19C

             e= 1.6*10-19C

                q = ne

                n = q/e

                     = 5*10-19C/1.6*10-19C

                      = 50 / 16

             n = 3