Question

to charges 80 micro columb and 40 micro columb are place at the certain distance apart .they are touched are kept at some distance. the ratio of initial to final force between them is​

Answer 1

Answer:

Ratio of initial force and final force is 0.89

Explanation:

Initial force between two charges is given as

$F_1 = \frac{k(80 \mu C)(40 \mu C)}{r^2}$

now when two charges are in contact with each other then the two charges will divide equally

so we will have

$q = \frac{80 + 40}{2} = 60 \mu C$

now again we have

$F_2 = \frac{k(60 \mu C)(60 \mu C)}{r^2}$

so we will have

$\frac{F_1}{F_2} = \frac{(80 \mu C)(40 \mu C)}{(60 \mu C)(60 \mu C)}$

$\frac{F_1}{F_2} = 0.89$

#Learn

Topic : Electrostatic force

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Answer 2

Answer:

Its 1:1

Explanation:

You ll find this line in your textbook

"The ratio of 2 opposite charges when placed at a certain distance apart from each other is 1:1"