to check the identity (a+b)³= a³+3ab(a+b)+b³ where a,b both are positive.
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(a+b)³ = ( a + b ) ( a + b ) ( a + b )
= ( a + b ) ( a + b )²
= ( a + b ) ( a² + 2ab + b² )
= a(a² + 2ab + b²) + b(a² + 2ab + b²)
= a³ + 2a²b + ab² + ba² + 2ab² + b³
= a³ + 3a²b + 3ab² + b³
So, (a+b)³= a³ + 3a²b + 3ab² + b³
= a³+3ab(a+b)+b³
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