Question

To code the 50 aminoacids in a polypeptide chain, what will be the minimum number of nucleotides in its cistron?
a)- 50
b)- 153
c)- 306
d)- 300​

Answer 1

Good evening beautiful,

Here's your answer

Cistron is a double stranded DNA segment which codes polypeptides.

For coding 50 amino acids 51 codons are needed (50 codons + 1 stop codon)

Each codon is triplet. And triplet have 3 nitrogen bases.

So number of nucleotide for 51 codons =51*3=153

So total number of nucleotides will 153 *2 =306(Cistron is a double stranded DNA segment which codes polypeptides. So adding nucleotides of both the strands)

Answer is (3)

Hope this helps you

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Answer 2

Answer:

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Answers

Cistron is a double stranded DNA segment which codes polypeptides.

For coding 50 amino acids 51 codons are needed (50 codons + 1 stop codon)

Each codon is triplet. And triplet have 3 nitrogen bases.

So number of nucleotide for 51 codons =51*3=153

So total number of nucleotides will 153 *2 =306

(Cistron is a double stranded DNA segment which codes polypeptides. So adding nucleotides of both the strands)