To complete a certain task, X is 40% more efficient than Y, and Z is 40% less efficient than Y. Working together, they
can complete the task in 21 days. Y and Z together worked for 35 days. The remaining work will be completed by A
alone in:
Answers
Given : X is 40% more efficient than Y, and Z is 40% less efficient than Y. Working together, they can complete the task in 21 days.
To find : remaining work will be completed by A alone in how many days
Solution:
Y's 1 day work = Y
X is 40% more efficient than Y
=> X's 1 day work = Y + (40/100)Y = 1.4Y
Z is 40% less efficient than Y
=> Z's 1 day work = Y - (40/100)Y = 0.6Y
Working together, they can complete the task in 21 days.
=> Total Works = 21 ( Y + 1.4Y + 0.6Y) = 63Y
Y and Z together worked for 35 days
=> work done = 35 (Y + 0.6Y) = 56Y
Remaining work = 63Y - 56Y = 7Y
remaining work will be completed by X = 7Y / 1.4Y = 5 Days
remaining work will be completed by A alone in 5 Days
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