Question

To complete a work, A takes 50% more time than B. If together
they takes 18 days to complete the work, then B takes the time to
dd the work in​

Answer 1

Answer:

i don't know

Step-by-step explanation:

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Answer 2

AnswEr:

GivEn:

• A takes 50% more than B
• Work done together in 18 days

To Find:

• How much time B takes to do same work?

Solution:

According to Question,

Let assume B complete any work in x days.

Again,

A complete same work (x) in ${\sf{ (x + \dfrac{x \times 50}{100} = \dfrac{3x}{2} )}}.$

✻ Work of both in 1 day = $\sf{ \dfrac{1}{18} }$

$\implies {\sf{ \dfrac{ 1}{x} + \dfrac{1}{( \dfrac{3x}{2} )} = \dfrac{1}{18} }}\\ \\ \implies{\sf{ \dfrac{1}{x} + \dfrac{2}{3x} = \dfrac{1}{18} }} \\ \\ \implies{\sf{ \dfrac{3+2}{3x} = \dfrac{1}{18} }} \\ \\ \implies{\sf{ \dfrac{5}{3x} = \dfrac{1}{18} }}$

After the cross Multiplication,

$\implies{\sf{ 3x \: = \: 5 \times 18} } \\ \\ \implies \huge\sf\underbrace\red{ x = 30\: days }$

Thus,

B takes 30 days to complete the same work.