Question

To complete a work, a takes 50% more time than

b. if together they take 18 days to complete the work, how much time shall b take to do it?

Answer 1

Answer:

30 days.

Step-by-step explanation:

We have,

B = 3/2 *A

→ A = 2/3 *B

One day's work, (A+B) = 1/18

(2/3 * B + B) = 1/18

5/3 *B = 1/18

One day's work of B = 3/90

B alone can complete the work in,

= 90/3

= 30 days.

Answer 2

Answer:

A : B

A : B3 : 2

A : B3 : 2[AB=150%100%=32]

A : B3 : 2[AB=150%100%=32]efficiency of work =2:3(Efficiency is always inversely proportion to time)

A : B3 : 2[AB=150%100%=32]efficiency of work =2:3(Efficiency is always inversely proportion to time)Total work = 18days×(2+3) unit

A : B3 : 2[AB=150%100%=32]efficiency of work =2:3(Efficiency is always inversely proportion to time)Total work = 18days×(2+3) unit= 90 units

A : B3 : 2[AB=150%100%=32]efficiency of work =2:3(Efficiency is always inversely proportion to time)Total work = 18days×(2+3) unit= 90 unitsB completes the work in

A : B3 : 2[AB=150%100%=32]efficiency of work =2:3(Efficiency is always inversely proportion to time)Total work = 18days×(2+3) unit= 90 unitsB completes the work in=90units3units/day= 30 days