To complete the following program to find numbers whose cube is less than 1000 which of
the following options would be the correct one?
N = 1
cube_of_N = N*N*N
While cube_of_N< 1000
if _________ then
Print N
N = N + 1
cube_of_N = N*N*N
end if
End while
(a) N < 1000
(b) N < N + 1
(c) N > 1
(d) N > 1000
no irrelevant answers plzz
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Answer:
Numbers less than N that are perfect cubes and the sum of their digits reduced to a single digit is 1
Given a number n, the task is to print all the numbers less than or equal to n which are perfect cubes as well as the eventual sum of their digits is 1.
Examples:
Input: n = 100
Output: 1 64
64 = 6 + 4 = 10 = 1 + 0 = 1
Input: n = 1000
Output: 1 64 343 1000
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