To construct a ray diagram we use two rays of light which are so chosen that it is easy to determine their directions after reflection from the mirror . Use these two rays to find the nature and position of the image of an object placed at a distance of 15 cm from a Concave mirror of focal length 20cm.Show using ray diagram .
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The candidate may choose the following rays:
(i) A ray parallel to the principal axis, after reflection, will pass through the principal focus of a concave mirror.
(ii) A ray passing through the center of curvature of a concave mirror after reflection is reflected back al;ong the same path.
Object distance, u=−15cm, focal length, f=−10cm, image distance, v = ?
Apply mirror formula,
v
1
+
v
1
=
u
1
∴
v
1
+
−10
1
=
−15
1
v
1
=
10
1
+
15
1
=
30
−3+2
=
30
−1
∴v=−30cm
The image is foamed at a distance of 30cm in front of mirror (negative sign means object and image are on the same side). It is real and inverted.
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