to construct a triangle given its base a base Indian and the difference of the other two sides
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Given ,
- the base BC a base angles CB and the difference of other two side AB-AC or AC-AB .
Required ,
- to construct the triangle ABC
There are following two cases
Case (i) Let AB > AC i.e. AB-AC is given .
Steps to construct ,
- draw the base BC and at point B make an angle say XBC equal to the given angle .
- cut the line segment BD equal to AB-AC from the ray BX.
- join DC and draw the perpendicular bisector say PQ of DC .
- let it intersect BX at a point A. join AC .
Then , ABC is a required Triangle.
Case (ii) Let AB< AC i.e. , AC - AB is given .
Steps to construction ,
- draw the base BC and at point B make an angle , say XBC equal to the given angle .
- cut the line segment BD equal to AC - AB from the line BX extended on opposite side of line segment BC .
- join DC and draw the perpendicular bisectors say PQ of DC
- let p q intersect BC at point A. join AC .
Then , ABC is a required Triangle
Justification ;
base BC and CB are drawn As given .
- the point a lies on the perpendicular bisector of DC .
- AD = AC
So, BD = AD - AB = AC - AB
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