Question

To construct a triangle, given its hase, a base angle and sum of other to sides.​

Answer 1

i don't answer but my pic

Answer 2

Step-by-step explanation:

1. Obtain the base, base angle and the sum of the other two sides. Let BC be the base, ∠ABC be the base angle and the sum AB + AC of the other two sides of a

triangle ABC.

2. Draw the base BC.

3. Draw ∠XBC of measure equal to that of ∠ABC.

4. From ray BX, cut-off line segment BD equal to the sum AB + AC of the other two sides

5. Join CD.

6. Draw the perpendicular bisector of CD meeting BD at A.

7. Join AC to obtain the required triangle ABC.

Examples: Construct a triangle ABC in which BC = 5 cm, AB + AC = 8.5 cm and ∠ABC = 60°.

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