To construct a triangle similar to a given ∆ABC with its sides 8/5 of the corresponding sides of ∆ABC, draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is:
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Question :- To construct a triangle similar to a given ∆ABC with its sides 8/5 of the corresponding sides of ∆ABC, draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is ?
Solution :-
we know that, if a traingle is constructed similar to another triangle with its sides (x/y) , then,
- The minimum number of points to be located at an equal distance is equal to x .
- Here x > y.
given that,
→ Constructed ∆ = (8/5) of ∆ABC
here,
- x = 8, y = 5 .
- x > y .
therefore, we can conclude that, the minimum number of points to be located at equal distance on Ray BX is 8.
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Answer:
8 is the correct answerof this question
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