Math, asked by samritkumarbhutia793, 4 months ago

To construct a triangle similar to a given ∆ABC with its sides 8/5 of the corresponding sides of ∆ABC, draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is:​

Answers

Answered by RvChaudharY50
37

Question :- To construct a triangle similar to a given ∆ABC with its sides 8/5 of the corresponding sides of ∆ABC, draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is ?

Solution :-

we know that, if a traingle is constructed similar to another triangle with its sides (x/y) , then,

  • The minimum number of points to be located at an equal distance is equal to x .
  • Here x > y.

given that,

→ Constructed ∆ = (8/5) of ∆ABC

here,

  • x = 8, y = 5 .
  • x > y .

therefore, we can conclude that, the minimum number of points to be located at equal distance on Ray BX is 8.

Answered by rs9888122878
0

Answer:

8 is the correct answerof this question

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