to construct the perpendicular bisector of a given line segment
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Given a line segment AB
open the compass more than half of the distance between A and B, and scribe arcs of the same radius centered at A and B.
Call the two points where these two arcs meet C and D. Draw the line between C and D.
CD is the perpendicular bisector of the line segment AB. Call the point where CD intersects AB E.
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The perpendicular bisector of a line segment is the line which is perpendicular to a given line segment and which divides it into two equal line segments. How to construct the perpendicular bisector of a line segment (by using just a straightedge and compass, without a triangle)?
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