Math, asked by lickballs999, 3 days ago

To cover a distance of 40 km, A takes 2 hours more than B. If A doubles his speed, it takes him 1 (1/2) hours more than B to cover a distance of 80km. To cover a distance of 90 km, how long will B take at the same speed?​

Answers

Answered by Tanishadutta
0

Step-by-step explanation:

Given :

Distance = 40 km

A takes 2 hrs more than B to cover 40 km

A takes 1.5 hrs more than B to cover 80 km

To find :

Time taken by B to cover 90 km

Formula used :

Distance = speed × time

Solution :

Let the speed of B be x kmph

⇒ Time taken by B to cover 40 km = 40/x

⇒ Time taken by A = (40/x) + 2

So, the speed of A = (20x)/(20 + x) ----(1)

Now,

Distance = 80 km

⇒ Time taken by B to cover 80 km = 80/x ----(2)

⇒ Speed of A when he doubles his speed = (40x)/(20 + x)

⇒ Time taken by A to cover 80 km = (40 + 2x)/(x) ----(3)

A.T.Q.,

From (2) and (3)

(80/x) + (3/2) = (40 + 2x)/x

⇒ 2 (40 + 2x - 80) = 3x

⇒ 2 (2x - 40) = 3x

⇒ 4x - 80 = 3x

⇒ 4x - 3x = 80

⇒ x = 80

⇒ Speed of B = 80 kmph

Distance = 90 km

Time taken by B = 90/80

∴ time taken by B to cover 90 km is one whole one by eight hrs.

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