To determine G the time of 20 oscillations of a simple pendulum of length 100 cm was observed to be 40 seconds. Calculate the maximum percentage error in measurement of g.
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T=2030sec ΔT=201sec
L=55cm ΔL=1mm=0.1cm
g=T24π2L
percentage error in g is
gΔg×100%=(LΔL+T2ΔT)100%
=⎝⎜⎜⎜⎛550.1+20302(201)⎠⎟⎟⎟⎞100%=6.8%
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