Question

To determine the acceleration due to gravity the time of 20 oscillations of a simple pendulum of length 200 CM was observed to be 40 second calculate the value of g and maximum percentage error in the value of g

Answer 1

Formulae

g = 4π²L / T²

Where g is the acceleration due to gravity, L the length of the pendulum and T the time taken for one oscillation.

L = 200/100 = 2m

T = 40 / 20 = 2 seconds

Substituting in the formula :

g = 4π² × (2 / 4)

g = 2π²

g = 19.74 m/ s²

The normal acceleration = 9.8 m/ s²

The error :

19.74 — 9.8 = 9.94

% error :

9.94 / 9.8 = 1.0143

1.0143 × 100 = 101.43%

Answer 2

Given,L=200cm=2m,T=40/20=2second,

Now ,

g=4 pi square L/T square

=4× 3.14×3.14×2/2×2

=19.72m/s square

And the perchantage error= 19.72-9.8=9.92