Question

To determine the number of valence electron of an element :
Number of valence electrons = number of lower values of IP before 1* highest jump.
BEGINNER'S BOX-4
IP, and IP, of Mg are 178 and 348 K. cal mol'. The enthalpy required for the reaction Mg → Mg2+ + 2e is
(1) + 170 Kcal
(2) + 526 Kcal
(3) - 170 K.cal
(4) -526 K.cal
The IP, IP, IP, IP, and IP of an element ar 7
likel​

Answer 1

Answer:

Mg(g)⟶Mg

+2

(g)+2e

−

is

Mg→Mg

+

→Mg

+2

so energy required for the reaction is 178+348=526 kcal/mol.