Question

To divide a line segment AB in the ratio 2 :5,a Ray AX is drawn such that angle BAX is acute. Then points are marked at equal intervals on AX. What is the minimum number of these points

Answer 1

Minimum number of points is 7

Step-by-step explanation:

If we have ratio m:n

Then minimum no of points is= m+n

As we have ratio 2:5

∴ minimum no of points = 2+5 = 7

Answer 2

minimum number of 7 points are required

Step-by-step explanation:

To divide a line segment AB in the ratio 2:5

Step1 : Draw a line segment AB  of some length

Step 2 :  Draw a line segment AX such that ∠BAX is an acute angle

Step 3:  Take 7 point on AX of Equal length one by one ( consecutively)

Step 4 :  Join 7th Point with B as a straight line

Step 5 : Draw a line parallel to line drawn in step 4 such that it passes through 2nd point of step 3 and intersect AB at M

M divides AB in to  2:5 Ratio.

hence ,

minimum number of 7 points are required

#Learn more:

To divide a line segment AB in the ratio 2:3 a ray AX is drawn such that angle BAX is acute . AX is then marked at equal intervals. what are the maximum numbers if these marks

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