Math, asked by shivanipal1410, 8 hours ago

To divide a line segment AB in the ratio 2 : 5, first a ray AX is drawn, so that ∠BAX is an acute angle and then at equal distances points are marked on the ray such that the minimum number of these points is : (a) 2 (b) 4 (c) 5 (d) 7. ​

Answers

Answered by srihari22211gmailcom
0

Correct option is

D

12

We should divide AX into 5+7=12 parts and draw a line parallel to BX from line no. 5 to AB.

Then this line will divide AX as well as AB in the ratio 5:7.

Hence, Option D is correct.

solution

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Answered by ishikatripathixb
0

Answer:

if we have ratio A : X

then minimum number of point is A + X

as we have ratio 2:5

therefore, minimum number of point = 2+5= 7

so, the correct answer is 7 ( d ) option

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