Question

to divide a line segment ab in the ratio 2 ratio 5 first array X is drawn so that angle b a x is an acute angle and then at equal distance point are marked on the array such that the minimum number of this points is​

Answer 1

Answer:

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minimum number of 7 points are required

Step-by-step explanation:

To divide a line segment AB in the ratio 2:5

Step1 : Draw a line segment AB  of some length

Step 2 :  Draw a line segment AX such that ∠BAX is an acute angle

Step 3:  Take 7 point on AX of Equal length one by one ( consecutively)

Step 4 :  Join 7th Point with B as a straight line

Step 5 : Draw a line parallel to line drawn in step

4 such that it passes through 2nd point of step 3 and intersect AB at M

M divides AB in to  2:5 Ratio.

in to  2:5 Ratio.hence ,

minimum number of 7 points are required

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Answer 2

Let the Parts of line be 2X and 3X 2X = x + x So 2X has 2 equal parts. 3X = x+x+x