Question

To divide a line segment AB in the ratio 3 : 7, first, a ray AX is drawn so that ∠BAX is
an acute angle and then at equal distances points are marked on the ray AX such that
the minimum number of these points is

Answer 1

$3 + 7 = 10$

.....

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Answer 2

10 points are required  To divide a line segment AB in the ratio 3:7

Step-by-step explanation:

To divide a line segment AB in the ratio 3:7,

Step1 : Draw a line segment AB  of some length

Step 2 :  Draw a line segment AX such that ∠BAX is an acute angle

Step 3:  Take 10 point on AX of Equal length one by one ( consecutively)

Step 4 :  Join 10th Point with B as a straight line

Step 5 : Draw a line parallel to line drawn in step 4 such that it passes through 3rd point of step 3 and intersect AB at M

M divides AB in to  3 : 7 Ratio.

10 points are required

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