Question

To divide a line segment AB in the ratio 4:5, first a ray AX is drawn making angle BAX an acute angle
and then points A1, A2, A3.... at equal distances are marked on the ray AX. At what point is point
B joined?​

Answer 1

$\huge\mathcal\pink{ANSWER:-}$

We know that to divide a line segment AB in the ratio m:n we have to follow the following steps of construction:

1.Draw a line segment AB of a given length by using a ruler.

2. Draw any Ray AX making an acute angle with AB.

3. Along AX mark off (m+n) points A1,A2,A3,….Am , A(m+1), A(m+n) such that AA1= AA2= A(m+n-1)A(m+n).

4.Join BA(m+n).

5. Through the point Am draw a line parallel to A(m+n) by making an angle equal to ∠AA(m+n) which intersects the line segment AB at point P.

The point P so obtained is the required point which divides AB internally in the ratio m:n.

Here, m= 5 , n= 7

Hence,the maximum number of points on the ray AX = 5+7= 12.

HOPE THIS WILL HELP YOU...

Answer 2

Answer:

These parallel lines divide line AB into 9 equal parts. So, to divide the line in the ratio 4:5, the first 4 portions will be taken and last 5 left as shown. ∴ Answer =A9.