Question

To divide a line segment AB in the ratio 5:6, draw a ray AX such that ∠BAX is an acute angle, then draw a ray BY parallel to AX and the points A1, A2, A3,…. and B1, B2, B3,…. are located to equal distances on ray AX and BY, respectively. Then, the points joined are
(A) A5 and B6
(B) A6 and B5
(C) A4 and B5
(D) A5 and B4

PLEASE GIVE PROPER ANSWER!!!​

Answer 1

Step-by-step explanation:

Therefore, total number of divisons on BY and AX is 5+6=11.

ΔAOX and BOY are similar, since AX∥BY

⇒∠X=Y and ∠A=B

∴ no. of divisions onB= 6

no. of divisions onA = 5

⇒ number of divisions on B= 6/5× number of divisions in A.

6/5 ×5=6

So, A5 should be joined to B 6

Answer 2

Answer:

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