Question

To divide a line segment AB internally in the ratio 5:7, first a ray AX is drawn so that ∠BAX is an acute angle and then at equal distances points are marked on ray AX such that the minimum number of these points is

​

Answer 1

Answer:

to divide a line segment AB in the ratio ,m : n, a ray AX making an acute ∠BAX, is drawn and then m + n points are marked at equal distances on the ray AX.

Here, m = 5, n = 7

Therefore, minimum number of points to be marked on AX = m + n = 5 + 7 = l2.