Math, asked by FROSTYYYY, 3 months ago

To divide a line segment BC internally in the ratio 3:4, we draw a ray BX such that

<CBX is an acute angle. What will be the minimum number of points to be located at

equal distances, on ray BX?​

Answers

Answered by sahuhinjilicut
0

Step-by-step explanation:

To divide a line segment BC internally in the ratio 3:4, we draw a ray BX such that

<CBX is an acute angle. What will be the minimum number of points to be located at

equal distances, on ray BX? your answer is in up .

I hope my answer will help you .

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