To divide a line segment BC internally in the ratio 3:4, we draw a ray BX such that
<CBX is an acute angle. What will be the minimum number of points to be located at
equal distances, on ray BX?
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To divide a line segment BC internally in the ratio 3:4, we draw a ray BX such that
<CBX is an acute angle. What will be the minimum number of points to be located at
equal distances, on ray BX? your answer is in up .
I hope my answer will help you .
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