To divide a line segment BC internally in the ratio 3 : 5, we draw a ray BX
such that ∠CBX is an acute angle. What will be the minimum number of points
to be located at equal distances, on ray BX
Answers
8 points are required To divide a line segment BC in the ratio 3:5
Step-by-step explanation:
To divide a line segment BC in the ratio 3:5,
Step1 : Draw a line segment BC of some length
Step 2 : Draw a line segment BX such that ∠CBX is an acute angle
Step 3: Take 8 point on BX of Equal length one by one ( consecutively)
Step 4 : Join 8th Point with C as a straight line
Step 5 : Draw a line parallel to line drawn in step 4 such that it passes through 3rd point of step 3 and intersect BC at M
M divides BC in to 3 : 5 Ratio.
8 points are required
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