Question

To divide a line segment BC internally in the ratio 3 : 5, we draw a ray BX

such that ∠CBX is an acute angle. What will be the minimum number of points

to be located at equal distances, on ray BX?​

Answer 1

Answer:

8

Explanation:

for 3:5 it should be 8;. 3+5

for dividing it into m:n the minimum no. of points will be m+n

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