Question

To divide a line segment BC of length 7 cm in the ratio 4:5 we draw a
ray BX such that CBX is an acute angle. What will be the minimum number
of points to be located at equal distance on ray BX?​

Answer 1

plz...send in pic form

Answer 2

9  points are required  To divide a line segment BC in the ratio 4:5

Step-by-step explanation:

To divide a line segment BC  in the ratio 4:5,

Step1 : Draw a line segment BC  of some length

Step 2 :  Draw a line segment BX such that ∠CBX is an acute angle

Step 3:  Take 9 point on BX of Equal length one by one ( consecutively)

Step 4 :  Join 9th Point with C as a straight line

Step 5 : Draw a line parallel to line drawn in step 4 such that it passes through 4th point of step 3 and intersect BC at M

M divides BC in to  4 : 5 Ratio.

9 points are required

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