Math, asked by shivam200454, 4 months ago

To divide a line segment BC of length 7cm in the ratio 4: 5 we draw a ray BX such that
∠CBX is an acute angle. What will be the minimum number of points to be located at
equal distances on ray BX?

Answers

Answered by ruttalajasu
9

Answer:

The maximum number of points=4+5=9

In this process, once line AX is drawn, it is divided into 9 equal parts.

The points are marked from point A towards X. The last point is then joined to point B to form line XB and passing through the points that were marked on AX. These lines can be drawn using set squares to ensure they are parallel.

These parallel lines divide line AB into 9 equal parts. So, to divide the line in the ratio 4:5, the first 4 portions will be taken and last 5 left as shown. ∴ Answer =A

9

solution

Answered by kavaiyaparth0007
3

Answer:

Answer is 9

Step-by-step explanation:

Thank you

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