Math, asked by shanabiroy12, 1 month ago

To divide a line segment PQ in the ratio 3: 7, we draw a ray PR such that <
QPR make an acute angle. What will be the minimum number of points to be

located at equal distances on ray PR

Answers

Answered by ramgarhiaak872594

1

Answer:

the minimum no. of points to be at PQ is 10 ( 7+3)

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