Question

To divide a line segment PQ in the ratio 4 : 5, first a ray PX is drawn so that ∠QPX is an acute angle and then at equal distances points are marked on the ray PX and the last point is joined to Q. Write the minimum number of these equal distances points on ray PX.
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Answer 1

Given : a line segment PQ in the ratio 4 : 5

a ray PX is drawn so that ∠QPX is an acute angle and then at equal distances points are marked on the ray PX and the last point is joined to Q.

To Find : minimum number of these equal distances points on ray PX.

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Solution:

To divide a line segment PQ in the ratio 4:5,

Step1 : Draw a line segment PQ  of some length

Step 2 :  Draw a line segment PQ such that ∠QPX is an acute angle

Step 3:  Take 0 point on PX of Equal length one by one ( consecutively)

Step 4 :  Join 9th Point with Q as a straight line

Step 5 : Draw a line parallel to line drawn in step 4 such that it passes through 4th point of step 3 and intersect PQ at M

M divides PQ in to 4 : 5 Ratio

9 points are required

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Answer 2

Answer:

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