Question

To divide line segment AB in the ratio m:n , a ray A X is drawn so that BAX is acute angle and then points are marked on ray AX at equal distance . Find the minimum of these points​

Answer 1

Answer:

We know that, to divide a line segment AB in the ratio m: n, first draw a ray AX which makes an acute angle ∠BAX, then marked m + n points at equal distance. Here, m = 5, n = 7 So, minimum number of these points = m+n = 5 + 7 = 12. Solution: (a) Given a line segment AB and we have to divide it in the ratio 5:6.

Step-by-step explanation:

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