To do a certain work, A and B . work on alternate days ,with B beginning the work on the first day. A can finish the work alone in 48 days. If the work get completed in 11 1/3 day then B alone can finish 4 times the same work in
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0
Answer:
ok wait..........m .......
Answered by
4
Answer:
27 days
Step-by-step explanation:
A and B are working alternately with B start first
total work time = 11 1/3 days
Thus B works =6 days and A works for 5 + 1/3 days
A can complete the work in 48 days
thus A’s work in 5 + 1/3 = 16/3 days = (1/48) * (16/3) = 1/9
So B’s work in 6 days = 1 - 1/9 = 8/9
B’s per day work = 8/54 = 4/27
So for B the days required to complete 4 time work
= 4/(4/27)
=4 * (27/4)
= 27 days
Hope it helps!
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