To do a certain work, A and B work on alternate days, with B beginning the work on the first day. A can finish the work alone in 48 clays. If the work gets completed in days. then B alone can finish 4 times the same work in:
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Answer:
Correct Answer - Option 2 : 6 days Given: Time taken by A to finish a task alone = 24 days Calculation: Let the total work be = 1 A alone can finish the task in 24 days ⇒ A's one-day work = 1/24 A and B complete the whole task in = 11 1 3 1113 days A and B work on alternate days, with B beginning so, we can say B will work only 6 days ⇒ A will work only 11 1 3 1113 - 6 = 5 1 3 513 days If A's one day work = 1/24 of work A completes in 1 day ⇒ A's 5 1 3 513 days work = 1/24 × 5 1 3 513 = 1/24 × 16/3 ⇒ 2/9 Remaining work = 1 - 2/9 = 7/9 ∴ B does the 7/9th part of the work in 6 days. Note- B, A, B, A, B, A, B, A, B, A, B, A/3 B completely 6-day work That's why we have taken the 6 days work by B alone.Read more on Sarthaks.com - https://www.sarthaks.com/2667828/certain-work-work-alternate-days-with-beginning-work-first-alone-complete-same-work-days