Math, asked by nikhildubey7311, 5 hours ago

To do a certain work, A and B work on alternate days, with B beginning the work on the first day. If the work gets

completed in 22 2/3days, if A can finish the work alone in 48 days then B alone can finish 11 times the same work in: ​

Answers

Answered by priyanshsharma45
3

Answer:

Step-by-step explanation:ate days, with B beginning the work on the first day. If the work gets

, A and B work on alternate days, with B beginning the work on the first day. If the work gets

completed in 22 2/3days, if A can finish the work alone in 48 days then B alone can finish 11 times the same work in: ​

Hold on, our servers are swamped. Wait for your answer to fully load.

completed in 22 2/3days, if A can finish the work alone in 48 days then B

o do a certain work, A and B work on alter, with B beginning the work on the first day. If the work gets

completed in 22 2/3days, if A can finish the work alone in 48 days then B alone can finish 11 times the same work in: ​

nate days, with B beginning the work on the first day. If the work gets

completed in 22 2/3days, if A can finish the work alone in 48 days then B alone can finish 11 times the same work in: ​

Answered by khushisupriyajha
0

Answer:

27 days

Step-by-step explanation:

Let the efficiency of A be 1 unit

Total work = 48 x 1 = 48 units

Working alternatively,

Time for which A work in days = days

Work done by A = units

Time for which B work = 6 days

Work done by B = 48 - = units

Efficiency of B = 128/18 units per day

Time taken by B to finish 4 times the work = 192/(128/18) = 27 days

Similar questions