Question

To do a certain work, B would take three times as long as A and C together and C twice as long as A and B together.The three men together complete the work in 10 days.How long would each take separately to complete the work

Answer 1

refer the attachment

Answer 2

24 days are Needed

Step-by-step explanation:

According to question,

1-day work of A, B & C=

A+B+C = $\frac {1}{10}$ -------------------(i)

A+C = 3B ------------------(ii)

A+B = 2C -----------------(iii)

On solving equation (i)&(ii),

we get B = 40 days

On solving equation (i)&(iii),

We get C = 30 days

Put the value of B & C as one day work in equation (i),

A = $\frac {1}{10} -\frac {1}{40} -\frac {1}{30} = \frac {(12-3-4)}{120}$

= $\frac {5}{120} = \frac {1}{24}$ part of work in one day,

so, to complete the work required day for A = 24 days.