Question

To do a certain work, C alone takes twice as long as A and B together, A alone takes 3 times as long as B and C together. All three together complete the work in 5 days. How long would each take to complete the work individually?​

Answer 1

Answer:

The work can be done by A alone in 20 days, B alone in days and C alone in 15 days.

Step-by-step explanation:

Given that, 3 times A's daily work =(B+C)'s 1 day's work.

Adding 1 time A's daily work to both sides, we get 4 times A's daily work.

⇒(A+B+C)'s daily work=4 times A's daily work. But (A+B+C)'s daily work=15.

A's daily work=1/20, A takes 20 days to do the work. Also, given 2 times C's daily work=(A+B)'s daily work. Adding 1 time C's daily work to both sides, we get 3 times C's daily work =(A+B+C)'s daily work=1/5

C's daily work=1/15, C takes 15 days to do the work.

B's daily work=15(120+115)=112, B takes 12 days to do the work.

∴ The work can be done by A alone in 20 days, B alone in days and C alone in 15 days.