To do a piece of work, B takes 3 times as long as A and C together, and C twice as long as
A and B together. If the three together can complete the work in 10 days, how long would
each take by himself?
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assume 100 units of work, so together they work @ 10 units/day
let A, B, C work @ a,b,c units /day
(a+c) = 3b ....... (i)
(a+b) = 2c ....... (ii)
a+b+c = 10 ..... (iii)
solving the system , we get
a = 25/6, b = 5/2, c = 10/3
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A will take 100/(25/6) = 24 days
B will take 100/(5/2) = 40 days
C will take 100/(10/3) = 30 days
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